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5m^2-23m+16=0
a = 5; b = -23; c = +16;
Δ = b2-4ac
Δ = -232-4·5·16
Δ = 209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{209}}{2*5}=\frac{23-\sqrt{209}}{10} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{209}}{2*5}=\frac{23+\sqrt{209}}{10} $
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